Webb11 apr. 2024 · 4 Two galvanometer coils each of resistance 10 Ω and full scale deflection of 10 mA connected in parallel are to be converted into a voltmeter of range 5 V. The resistance to be connected in series with combination, is A. 2.5Ω A. 450 c. 4900 D. 260 D WebbResistance of galvanometer by half deflection method . Here, current will flows through th circuit when key k1 is closed and k2 is open. The current flowing through the galvanometer is proportional to the deflection in it. Where, E - emf f the cell. R - resistance from the resistance box G - galvanometer resistance for current I θ ...
To Determine Resistance of a Galvanometer By Half ... - Learn CBSE
WebbInsert key k1. Adjust the value of R such that the galvanometer shows a certain deflection. Record the observations in a tabular column. Repeat the experiment by changing the … WebbTake out the plugs of calculated resistance R from the resistance box. By using a key, adjust the movable contact of the rheostat such that the deflection of the galvanometer becomes maximum. Note both the … fanfiction sleeping beauty
UNIT-2 Part-1 Measurement OF Resistance - UNIT – II …
Webb11 apr. 2024 · Find out all about Galvanometer Constant, its importance, and how it affects the performance of Moving Coil Galvanometers. ... such as air resistance, is used to reduce the oscillations of the pointer. ⇒ Theory: The torque on the coil is given by the product of the magnetic field, ... WebbThe maximum value of the current that can be measured by the galvanometer is 𝐼 . Every point on the dial is thus a fraction of the current: half deflection means a current of 𝐼 2 , quarter deflection is 𝐼 4 , and so on.. We ideally want to add a certain amount of resistance to the galvanometer, such that the total resistances make the current 𝐼 . WebbThe resistance of a galvanometer is 100 Ω . A shunt of 5 Ω is connected to it to convert it into an ammeter. The internal resistance of the ammeter is A 5.2 Ω B 4.8 Ω C 4.6 Ω D 4.2 Ω Medium Solution Verified by Toppr Correct option is B) Req= 100+5100×5= 105500=4.8Ω (since both the resistances are in parallel) Was this answer helpful? 0 0 fanfiction sly cooper